75-Sort Colors
100-Same Tree | Links:
题意
Given an array nums with n objects colored red, white, or blue, sort them in-place so that objects of the same color are adjacent, with the colors in the order red, white, and blue. Here, we will use the integers 0, 1, and 2 to represent the color red, white, and blue respectively. Follow up:
- Could you solve this problem without using the library’s sort function?
- Could you come up with a one-pass algorithm using only O(1) constant space?
Example 1:
Input: nums = [2,0,2,1,1,0]
Output: [0,0,1,1,2,2]
Example 2:
Input: nums = [2,0,1]
Output: [0,1,2]
Example 3:
Input: nums = [0]
Output: [0]
Example 4:
Input: nums = [1]
Output: [1]
思路
- 特殊排序
- 三指针: start记录0的位置,end记录2的位置 -> 遇0swap到start, 遇2swap到end
class Solution(object):
def sortColors(self, nums):
"""
:type nums: List[int]
:rtype: None Do not return anything, modify nums in-place instead.
"""
if not nums: return []
start, end = 0, len(nums)-1
i = 0
while i <= end:
if nums[i] == 0:
nums[i],nums[start] = nums[start],nums[i]
i += 1
start += 1
elif nums[i] ==1:
i += 1
else:
nums[i],nums[end] = nums[end],nums[i] #此处不可i++, 否则将未排序元素置换到前面
end -= 1
分析:
- Time: O(n)
- Space: O(1)